8x^2-6x+1=15

Solution for 8x^2-6x+1=15 equation:

8x^2-6x+1=15

We move all terms to the left:

8x^2-6x+1-(15)=0

We add all the numbers together, and all the variables

8x^2-6x-14=0

a = 8; b = -6; c = -14;
Δ = b2-4ac
Δ = -62-4·8·(-14)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-22}{2*8}=\frac{-16}{16}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+22}{2*8}=\frac{28}{16}
=1+3/4
$